PreCalculus
Precalculus is an interesting area of math for students because of its multipurpose nature. It reviews previously learned topics like trigonometry, introduces new topics like matrices and determinants, and prepares students for a formal course in calculus for the following year. Precalculus is sometimes referred to as Algebra 3 because it builds upon basic algebraic concepts that were learned in high school. In some educational institutions, precalculus is divided into separate algebra and trigonometry courses to provide a solid foundation for a calculus course.
Effective and Convenient PreCalculus Help Is Available Online
Many students struggle with precalculus and need additional assistance. Reliable online help for homework assignments is available here at 24HourAnswers.com. Our online help for homework comes in two forms: you can submit your materials to our precalculus specialists who will offer guidance and advice to help you arrive at the appropriate solutions. Another option is to sign up for a live online session with a knowledgeable precalculus tutor who will provide oneoneone instruction to help you increase your level of understanding.
We Can Help You Master the Typical Content Found in Most PreCalculus Courses
Typical content for a regular precalculus course includes:
 functions and their graphs
 polynomial and rational functions
 exponential and logarithmic functions
 trigonometry
 systems of equations and inequalities
 matrices and determinants
 sequences, series, and probablility
While all these topics are important, it is fair to say that the topic of exponential and logarithmic functions is the most widespread in various fields of study, from business math to theoretical physics. As an interesting example, consider the following equation where we would like to solve for x:
e^{x} + 2e^{x} = 3
A quick review of three basic logarithm rules:
product rule: ln (ab) = ln a + ln b
quotient rule: ln (a/b) = ln a  ln b
power rule: ln a^{n} = n ln a
shows that none will be helpful here. One technique for solving this equation is to multiply both sides by e^{x}. The result is:
e^{2x} + 2 = 3e^{x}
After subtracting 3e^{x} from both sides, we have:
e^{2x}  3e^{x} + 2 = 0
After careful consideration of this equation, you may recognize it as a quadratic, with e^{x} taking the place of x. We can therefore factor this just as we would any quadratic equation:
(e^{x}2)(e^{x}1) = 0
Setting each factor equal to zero, we have:
e^{x}2 = 0 and e^{x}1 = 0
Adding 2 and adding 1 to the left and right equations, respectively gives:
e^{x} = 2 and e^{x} = 1
Now, finally, in each case we can take the natural log of both sides:
ln e^{x} = ln 2 and ln e^{x} = ln 1
Remembering that ln e^{x} = x, we have our two solutions:
x = ln 2 and x = 0
This example has served to review some of the basic properties of logarithms and to illustrate an early creative twist that was necessary for solving the given equation.
Get the PreCalculus Help You Need Today!
To fulfill our mission of educating students, our online tutoring centers are standing by 24/7, ready to assist students who need extra practice in precalculus.

