1. A mutation in a gene often results in a reduction of the product of that gene The term for this type of mutation is
A) codominance
B) incomplete dominance
c) gain of function
D) multiple alleles
E) loss of function or null (in the case of complete loss)

2. A situation in which there are more than two alternative forms of a given gene would be called
A multiple alleles
B) alternation of generations
C) codominance incomplete
D dominance
E) hemizygosity

3. A condition in which one gene pair masks the expression of a nonallelic gene pair additive is called
A) codominance
B) epistasis
C) dominance
D) recessiveness
E) alleles

4. With which of the following would hemizygosity most likely be associated? A) codominance
B) incomplete dominance
C) trihybrid crosses
D) X-linked inheritance
E) sex-limited inheritance

5. The blood types LM and LN are expressed equally when present. Therefore, a person with the genotype, LM/LN, would exhibit the phenotype: A) M
B) N
C) MN
D) AB
E) A

6. The example in problem #5 would be representative of
inheritance.
A) dominant-recessive
B) incomplete dominant
C) multiple allelic
D) codominant
E) epigenetic

7. In a population, the expression of genes may occur in a range due to environmental influence.
For example, a dominant trait may only be observed in 30% of the population even though the alleles are present in 90% of the population. The 30% observation could be due to
A) complementation
B) expressivity
C) penetrance
D) epistasis
E) genomic imprinting

8. In the Bombay phenotype, the Fut1 gene is defective, thereby not producing the enzyme, galactosyltransferase.
A) True
B) False (Correct if false)

Angelman Syndrome can result when a portion of the paternal copy of chromosome 15 is deleted.
A) True
B) False (Correct if false)

10. In chickens, the sexual genotype for males is zz, while that for females is zw. If a gene for the recessive trait, long feathers is found on the Z gene, what percentage of males would have long feathers if the mother has long feathers and the father is heterozygous for short feathers.
A) 50%
B) 25%
C) 75%
D) 33%
E) 0%

11. In the ABO blood system, the A allele codes for the enzyme that adds the sugar to the H substance.
A) galactose
B) fucose
C) N acetylglucosamine
D) glucose
E) N-acetvlgalactosamine

12. in crosses involving the intermediate trait in incomplete dominance, the phenotypie ratio would typically be A 3:1, B 3:3:1 C 1:2:1 D 9:3:4 E 1:1

13. in determining probability, the probability will range from 0 to 1.
A) True
B) False (Correct if false)

14. Wild-type genotypes can be designated with the + sign.
A) True
B) False (Correct if false)

15. Dominant lethal genes are never observed in the population.
A) True
B) False (Correct if false)

3. The trait of medium-sized leaves in iris is determined by the genetic condition PP' Plants with large leaves are PP, whereas plants with small leaves are P'P'. A cross is made between two plants each with medium-sized leaves. If they produce 80 seedlings, what would be the expected phenotypes, and in what numbers would they be expected? What is the term for this type of inheritance? (10 pts.)

2. Many of the color varieties of summer squash are determined by several interacting loci: AA or Aa gives white, aaBB or aoßb gives yellow, and aabb produces green. Assume that two fully heterozygous plants are crossed. Give the phenotypes and phenotypic ratio of the offspring. What type of gene interaction does this represent? (10 pts.)

3. The enzyme glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as a recessive gene on the X chromosome in humans. A phenotypically normal woman (whose father had G6PD) is married to a normal man (10 pts.).
a) List the genotypes of the woman and man.
b) What fraction of their sons would be expected to have G6PD?
c) If the husband had G6PD, would it make a difference in your answer in part (b)? Explain.
d) Determine the probability of having 5 children where three were normal females and 2 males had G6PD. (You may use any method to determine probability).

Two sex-influenced traits occur simultaneously, pattern baldness and short index fin these traits are dominant (homozygous and heterozygous) in men and recessive in women. A heterozygous bald man with long index fingers marries a heterozygous, bald woman.
A) Determine the genotypes for the male and female.
B) Determine ratios for their children. [Hint: You must account for both male and fem types in the offspring.

Determine the phenotypic ratio from a cross between a woman with A type blood (whose father was type 0) and a man who is type B (whose mother was type O) where both the woman and man are heterozygous for the H substance (10 pts.).

1. A mutation in a gene often results in a reduction of the product...