QUESTION 1
1. Question One. Suppose that you work for a pharmaceutical company that is conducting a pilot study to test the efficacy of a newanti-depressant drug. The "well-being" of individuals is measured on a 20 point Likert scale, where higher scores indicate higher levels of well-being. Nine subjects participating in this trial respond to the questions on the well-being scale before taking a course of the new anti-depressant and after completing an 8 week course of treatment with the new anti-depressant. The results are shown in the Question One worksheet of the Quiz Five Data. Does the data provide sufficient evidence to conclude that the mean well-being is higher after taking the new anti-depressant? Conduct a hypothesis test at α = .05 to determine if the mean well-being is higher after taking the drug. This can be expressed in the following hypotheses: H0:μpost-μpre ≤ 0 versus H1:μpost-μpre>0 .
A. Cannot reject the null hypothesis because p-value = .9863 > α = .05 . Mean well-being is not significantly higher after taking the anti-depressant.
B. Cannot reject the null hypothesis because p-value = .0069 < α = .05 . Mean well-being is not significantly higher after taking the anti-depressant.
C. Reject the null hypothesis because p-value = .0069 < α = .05 . Mean well-being appears to be higher after taking the anti-depressant.
D. Reject the null hypothesis because p-value = .01375 < α = .05 . Mean well-being appears to be significantly higher after taking the anti-depressant.

QUESTION 2
1. Question Two. The HRO for Qualtrix Corp. was concerned that the mean age of mid-level managers in their two manufacturing plants was signficantly different . To test this claim, a random sample of n1=18 mid-level managers in the San Jose facility and n2=20 mid-level managers in the Burlington facility were selected. Does there appear to be a signficiant difference in the mean age of mid level managers at the two facilities? Test at α =.10. What do you conclude? Assume unknown and unequal variances.
A. Reject the null hypothesis since p-value =.00023 is less than α =.10.
B. Cannot reject t he null hypothesis since p-value =.00023 is less than α =.10.
C. Reject the null hypothesis since p-value =.000114 is less than α =.10.
D. Cannot reject the null hypothesis since p-value =.000114 is less than α =.10.

QUESTION 3
1. Question Three. A market researcher would like to know the market share for a new fitness watch it is considering offering. They believe that the product will be successful if more than 20% of the existing market would purchase the new watch . The watch was demonstrated to 200 fitness enthusiasts. After the demonstration each was asked to indicate if they would purchase the new watch(Yes=1 or No =0). The results are shown in the worksheet Question Three. Conduct a hypothesis test using this data to determine if the true proportion, π, is greater than 20%. Use α=.01. What do you conclude?
A. p-value = .108 > α =.01. Reject the null. There is enough evidence to conclude that the true proportion of the current market who would buy the watch exceeds 20%.
B. p-value = .108 > α =.01. Cannot reject the null. There is not enough evidence to conclude that the true proportion of the current market who would buy the watch exceeds 20%.
C. p-value = .2159 > α =.01. Reject the null. There is enough evidence to conclude that the true proportion of the current market who would buy the watch exceeds 20%.
D. p-value = .2159 > α =.01. Cannot reject the null. There is not enough evidence to conclude that the true proportion of the current market who would buy the watch exceeds 20%.

QUESTION 4
1. Quetion Four. The mean diameter of a fastener used in a component is supposed to be equal to 1.5 cm. A random sample of 6 of these fasteners is routinely taken from the production process and tested. Assume that the fastener diameters are normally distributed with unknown standard deviation. The results of the most recent sample is shown in the worksheet Question Four. Conduct a hypothesis test to determine if the true mean diameter, μ, for the process differs from 1.5 cm. Use α=.05. What do you conclude?
A. p-value = .1797 > α=.05. Reject the null hypothesis. There is enough evidence to say that the mean diameter differs from 1.5 cm.
B. p-value = .1797 > α=.05. Cannot reject the null hypothesis. There is not enough evidence to say that the mean diameter differs from 1.5 cm.
C. p-value = .3593 > α=.05. Reject the null hypothesis. There is enough evidence to say that the mean diameter differs from 1.5 cm.
D. p-value = .3593 > α=.05. Cannot reject the null hypothesis. There is not enough evidence to say that the mean diameter differs from 1.5 cm.

QUESTION 1 1. Question One. Suppose that you work for a pharmaceut...