1. How many moles of aluminum chloride must decompose in order to form 18.3g of aluminum?

2. What mass of aluminum will be produced if 23.2 L of chlorine is produced at STP?

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1. How many moles of aluminium chloride must decompose in order to form 18.3 g of aluminium?

2 AlCl3 → 2 Al + 3 Cl2

We see that 2 moles of aluminum chloride produce 2 moles of aluminum. Molar mass of aluminum is 27 g/mol, meaning that 2 moles of aluminum chloride produce 2 moles or 54 g (2 x 27 g) of aluminum.

There are two ways we can approach this problem, both are correct and will give the same solution in the end.
a) We make a proportion - 2 moles of AlCl3 : 54 g of Al = X : 18.3 g of Al...

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