My drug stock is 1mg/ml in 100% methanol (3mM). I need to prepare two solutions of 1 µm and 10 µm. The finals solvent concentrations should be 3% methanol. How can I do it? How do you calculate the final solvent concentration?

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Drug’s concentration is 1mg/mL which is 3mM(or 3000µM) solution in methanol. We need to dilute them to 10µM
and 1µM and final solution to be in 3% methanol.
According to that, we have to dilute it 300times for first solution and 3000times for second. We need final solutions
in 3% methanol. Our diluting solution would be 3% methanol.
Here’s an example if you want to make 100mL of these solutions. If other volume is required, it is easily calculated
by multiplying or dividing by certain number....

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