# You will create a new List class that holds a singly linked list of...

## Question

You will create a new List class that holds a singly linked list of Course pointers. You will implement the linked list as we saw in class, with no dummy nodes. The List class will contain the following:
• a data member for the head of the list
• a data member for the tail of the list
• a constructor
• a destructor to clean up the dynamically allocated memory
• a member function with the prototype void add(Course*) that adds a new course to the list
◦ the new course will be added in its correct position in the list, in ascending (increasing) order by course, using the Course class’s lessThan() function
◦ you will need to implement a Node class, as we saw in class
• a print() member function that prints the courses to the screen
◦ after all data is printed, indicate which course is at the head and which course is at the tail

## Solution Preview

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#include <iostream>
using namespace std;
#include <string>

#include "List.h"

}

List::~List() {
Node* nextNode;

while (currNode != 0) {
nextNode = currNode->next;
delete currNode->data;
delete currNode;
currNode = nextNode;
}
}

if (course == 0) {
return;
}

// make new node
Node * n = new Node;
n->data = course;
n->next = 0;

// empty list
tail = n;
return;
}

return;
}

// add to the end of list
if (tail->data->lessThan(course)) {
tail->next = n;
tail = n;
return;
}...

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