QuestionQuestion

The following ciphertext was encrypted by an affine cipher modulo 26: CRWWZ. The plaintext starts ha. Decrypt the message.

Solution PreviewSolution Preview

These solutions may offer step-by-step problem-solving explanations or good writing examples that include modern styles of formatting and construction of bibliographies out of text citations and references. Students may use these solutions for personal skill-building and practice. Unethical use is strictly forbidden.

H -> C and A-> R. From here results a system of two equations, namely:
7*a+b=2 (mod 26)
0*x+b= 17 (mod 26) => b=17
We plug the value of b into the first equation to find out “a”.
7*a+17=2 (mod 26)=> 7*a= 2-17 (mod 26) = -15 (mod26) =26-15=11 (mod 26).
So 7*a= 11 (mod 26) => a= 7^(-1)* 11 (mod 26)
But the inverse of 7 (modulo 26) is 15 because 7*15=105=1 (mod 26).
So a= 15* 11 (mod 26) =165 (mod 26) = 9...

By purchasing this solution you'll be able to access the following files:
Solution.docx.

50% discount

Hours
Minutes
Seconds
$6.00 $3.00
for this solution

or FREE if you
register a new account!

PayPal, G Pay, ApplePay, Amazon Pay, and all major credit cards accepted.

Find A Tutor

View available Cryptography Tutors

Get College Homework Help.

Are you sure you don't want to upload any files?

Fast tutor response requires as much info as possible.

Decision:
Upload a file
Continue without uploading

SUBMIT YOUR HOMEWORK
We couldn't find that subject.
Please select the best match from the list below.

We'll send you an email right away. If it's not in your inbox, check your spam folder.

  • 1
  • 2
  • 3
Live Chats