See below file with the two questions.

**Subject Computer Science Cryptography**

See below file with the two questions.

Question 2

We use the provided information that

• TH encrypted gives GW and

• HE encrypted gives R3.

We also use the decryption function P =a*C + b (mod 37*37), where P is the plaintext digraph and C is the ciphertext digraph.

P =a*C +b (mod 1369)

TH =37*29 + 17 = 1090

GW = 37* 16 + 32 = 624...

We use the provided information that

• TH encrypted gives GW and

• HE encrypted gives R3.

We also use the decryption function P =a*C + b (mod 37*37), where P is the plaintext digraph and C is the ciphertext digraph.

P =a*C +b (mod 1369)

TH =37*29 + 17 = 1090

GW = 37* 16 + 32 = 624...

This is only a preview of the solution. Please use the purchase button to see the entire solution

Cryptography & Information Security Problems - Ciphertext Decryptions

$10.00

Computer

Science

Cryptography

Security

Ciphertext

Plaintext

Hill

Caesar

Affine

Vigenere

Substitution

Known

Attack

Key

Gcd

Greatest

Common

Divisor

Mod

Inverse

Prime

Language

Frequency

Analysis

Length

Computer

Science

Cryptography

Security

Ciphertext

Plaintext

Hill

Caesar

Affine

Vigenere

Substitution

Known

Attack

Key

Gcd

Greatest

Common

Divisor

Mod

Inverse

Prime

Language

Frequency

Analysis

Length

Hash Functions & El Gamal Signature Scheme

$5.00

Computer Science

Cryptography

Hash Function

Collision

Preimage

El-Gamal

Birthday Paradox

Signature

RSA Example

$3.00

RSA

Algorithm

Public

Key

Encrypted

Message

Eavesdropper

Ciphertext

Decrypt

Cryptography

Computer

Science