QuestionQuestion

You know that for comparison-based sorting algorithms it is impossible to design a linear time algorithm, since the lower bound for comparisons is Ω(nlogn). Can you design a comparison-based sorting algorithm that takes linear time on half of its inputs of size n, i.e. n!/2 inputs? Justify your answer.

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No, because the height of the tree will be roughly log(n!/2). Or, in this case, it means that...
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