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The order of growth for each function is given by the dominant term (the term of the highest degree). In order to be easier for ordering the functions by their asymptotic growth rate it is necessary to process some of them.
2^logn = n =O(n) (according the basic properties of Math operations).
2^10=1,024 therefore O(1) (since it is a contant)
4nlogn +2n is O(nlogn)
3n+100logn is O(n)...
2^logn = n =O(n) (according the basic properties of Math operations).
2^10=1,024 therefore O(1) (since it is a contant)
4nlogn +2n is O(nlogn)
3n+100logn is O(n)...
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