See below.

**Subject Computer Science Information Theory**

See below.

Part a)

Each of the 5 factors is irreducible polynomial, so the problem is equivalent with finding the number of divisors. Considering each of the 5 factors as divisors (a, b, c, d, e), we obtain 32 divisors, so there are 32 cyclic codes of block length 15. We also recall that when multiplying two of the factors, the operation is preserved (we also obtain a cyclic code from the product of two or more cyclic codes)....

Each of the 5 factors is irreducible polynomial, so the problem is equivalent with finding the number of divisors. Considering each of the 5 factors as divisors (a, b, c, d, e), we obtain 32 divisors, so there are 32 cyclic codes of block length 15. We also recall that when multiplying two of the factors, the operation is preserved (we also obtain a cyclic code from the product of two or more cyclic codes)....

This is only a preview of the solution. Please use the purchase button to see the entire solution

Java Programming Assignment

$8.00

Java Programming

Computer Science

Program

Code

Programming

Application

C-Family Programming Assignment

$6.00

C-Family Programming

Computer Science

C++

Program

Customer ID

C-Family Programming Assignment

$8.00

C-Family Programming

Computer Science

Radix-Sort

Integer

Algorithm

CountSort

Algorithms Assignment

$1.00

Algorithm

Computer Science

Graphs

Programming Language

Programming

Analysis

Computer Science Questions

$2.00

Binary representation

Hexadecimal

Decimal

ASCI

Substraction

Byte

Bit

MB

Pixel

Video Memory