## Question

The minimum integer is 0

The sum of even integers is 0

The count of positive integers in the sequence is 0

This means that using all numbers your program reads (including the last number 0), you need to compute the minimum, the sum of even integers (can be divided by 2, "num%2 == 0") and count how many positive integers (are greater than 0) in the sequence.

Note that the above is an output for the first test case. For other test cases, you will have different numbers.

Do not prompt to query for the numbers. The number 0 is included in the sequence of integers and should be included in all of your calculations.

Test Case #1

0

Test Case #2

-1 2 0

Test Case #3

-1 -2 -45 -90

1 23 678 90

0

Test Case #4

4 2 0 1 3

Output

Test Case #1

The minimum integer is 0

The sum of even integers is 0

The count of positive integers in the sequence is 0

Test Case #2

The minimum integer is -1

The sum of even integers is 2

The count of positive integers in the sequence is 1

Test Case #3

The minimum integer is -90

The sum of even integers is 676

The count of positive integers in the sequence is 4

Test Case #4

The minimum integer is 0

The sum of even integers is 6

The count of positive integers in the sequence is 2

## Solution Preview

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public static void main(String[] args) {int sum = 0;

int count = 0;

int minimum = 0;

int integer = 1;...