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The assignment includes three projects. You have to know what it means n factorial. The factorial of a nonnegative integer n is denoted as n! (pronounced “n factorial”) is defined as n! = n * (n-1) * … * 1 for n greater than or equal to 1 and n! = 1 for n = 0. For example 4! = 4 * 3 * 2 * 1 which is 24. Project a). Write an application that asks user to input a nonnegative integer and computes and prints its factorial. For next two projects I will give you some optional math information. It is shown that every smooth function may be presented as a Taylor series of infinite number of items sum of which is converged to this function. An important example of such a function is the exponential function exp{x} that is e x where e is Euler number 2.71828183…, and x is decimal number. Its Taylor series looks like e x = 1 + x /(1!) + x 2 /(2!) + x 3 /(3!) + … (1) So to find exp{x} we need to find the sum of infinite number of items in (1). We will use (1) to estimate the e x . But we can use only a finite number n of items in (1). e x 1 + x /(1!) + x 2 /(2!) + … x n /(n!) (2) Therefore we will calculate the e x with an error that is Rn = e x - [1 + x /(1!) + x 2 /(2!) + … +x n /(n!)] (3) It may be shown that 2 Rn = 1 ( 1)! e n x n (4) The number ε is located between 0 and x and depends from x and n. For whichever fixed value x the absolute error Rn in (3) converges to 0 when n converges to infinity: R 0 n when n . So for whichever fixed value x the function exp{x} may be evaluated as (2). There may be found a number n for which the absolute error Rn will become less then whichever positive given in advance small number. If x = 1 we will estimate the value of Euler number e as e 1 + 1/(1!) + 1/(2!) + … + 1/( n!) (5) In this case the error of estimation is Rn = ( 1)! e n , where 0 1 1 3 e e e e . So for Euler number e the absolute error of estimation e is Rn < 3 ( 1)! n (6) If 0 < x < 1 we will use estimation (2) with absolute error Rn < 3 ( 1)! n (6a) If x > 1 the error of approximate equation (2) will be bigger. Let the first whole number bigger than x is N, N-1 < x <= N. Then from (4) because 3 x N N e e e and n n 1 1 x N we will obtain Rn < 1 3 ( 1)! N n N n (7) 3 And this error will converge to 0 when n . If x < 0 the series (2) is sign-changing, e in (4) is less than 1. If |x| < 1, then Rn < 1 ( 1)! n (8) In this case error (8) of approximate equation (2) is the smallest one. If x < 0 and |x| > 1 the n 1 n 1 x N where N-1 < |x| <= N. Then the absolute error Rn < 1 ( 1)! n N n (9) It is bigger then (8) but less then (7). Project b). In math there are some very useful constants such as (you are using it to find circumference and area of a circle), natural number e, etc. Their values may be estimated using their Taylor’s series. Use equation (5) to approximate the natural Euler number e. The sum of the right side of (5) converges to the actual value of the natural number e with increasing the number n of items in this sum. If n = 0 e 1. If n = 1 e 1 + 1/(1!) = 2. If n = 2 e 1 + 1/(1!) + 1/(2!) = 2.5 If n = 3 e 1 + 1/(1!) + 1/(2!) + 1/(3!) 2.67. Pay attention that the sum of any finite number n of item in (5) cannot exceed the limiting value of e despite of the fact that every item in the right part of (5) is positive and number n of items is not limited (try to explain why?). 4 Write an GUI application that will help you to investigate how quick the right part of (5) converges to its left part. Your code should print a table with value of estimated e by using n = 0, n = 1, … , n = 10 items in the right part of (5). Calculate the running error (6). Compare your results with actual value of e that approximately can be represented by Math.E. Here Math is the Java API class that is located in the package java.lang. This package is automatically imported in every Java class. The E is a static public final (constant) data member of the class Math. Advanced version of project b. Ask user with what precision (absolute error) user want to calculate the value e, find the smallest number of items n in (5) that will satisfy this demand. It means that running error should be less then precision given by user. Show the results. Project c). In math it is often used the expression e x , where x is a decimal number and e is the natural number estimated in the Project b). The Taylor’s series for estimating e x is (1) and (2) approximates this value. The value of x may be positive or negative. If x = 0 the value e x equals to a constant (guess what?). The right side of (2) converges to its left side quicker when |x| < 1 and slowly when |x| > 1 (guess why?). If x < 0 the right sight of (2) is a sign alternative series where the items with x in odd degree are negative and items with x in even degree are positive. Because of that the sum in the right side of (2) may be and less and more than the value on the left side. But the absolute value of the difference between the sum of members on the right side and the value on the left side of (2) should decrease with increasing the number of items n. Write an application that will estimate e x by using (2) with running error (6a), or (7), or (8), or (9). Calculate e x with n = 1, n = 2, … , n = 10 items in (2). Advanced Project c. Write an application that tells user that it will calculate e x . Ask user the value of x and the precision with which e x 5 should be calculated. Compare this precision with corresponding running error to satisfy the user demand. In your output show what are values of the Math.exp(x), e x , the user’s precision epcilon and number of items n that satisfies the precision epcilon. Use your code to calculate e x for -1 < x < 0, x < -1, x > 0, x = 1, x > 1 and x = 0. Write a client class with GUI that will perform all tasks for Project a), Project b), and Project c). Do repetition statement as simple and effective as possible.

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import java.util.*;

* Projects Class containing static methods
* implementing Math operations and user
* interactivity for Projects A, B, and C
public class Projects {

// Method to recursively compute Factorial
public static long factorial(int n) {
    if (n == 0) {
      return 1;
    } else {
      return n*factorial(n-1);

// Project A execution and user interaction
public static void ProjectA() {
    System.out.println("--- Factorial Calculator Program ---");
    Scanner s = new Scanner(;
    while (true) {
      try {
       System.out.print("Please enter a nonnegative integer: ");
       int n = Integer.parseInt(s.nextLine());
       if (n < 0) {
          System.out.println("ERROR: Invalid input");
       System.out.println(n+"! = "+factorial(n));
      } catch (Exception e) {
       System.out.println("ERROR: Invalid input");

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