Then shifts the new signal by 12.5 ms (actually it is 25 ms because it is shifting for the shifted signal) and continue shifting until the signal ends (the given signal's window is about 215 ms) and finally average them all.
These solutions may offer step-by-step problem-solving explanations or good writing examples that include modern styles of formatting and construction of bibliographies out of text citations and references. Students may use these solutions for personal skill-building and practice. Unethical use is strictly forbidden.%12.5ms corresponds to 64 points in the signal (64*0.0002-0.0002=0.0126 = 12.5ms)
%so we will shift by 64 points each round.
%The number of shifts is the length of the signal divided by 64, so when we
% shift the signal number_of_shifts times it is back to the original signal and we don't shift anymore.
number_of_shifts = length(ABR)/64;
%We make an empty matrix to put in each row a shifted version of the previous row...
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