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Counting from the right, retrieve the 3rd digit of the Integer (101012199). The 3rd digit from the right would correspond to the position marked with an asterisk in ------*--. Do _NOT_ use indexing or slicing (i.e., do not use (i.e., variable[index] or variable[start_of_slice:end_of_slice]) to accomplish this; you _MUST_ use the integer division and modulation operators. These operators will compute the floored quotient and remainder respectively. You have to create it in a way you can find a digit in this position every time example
If I gave you the number 123 and asked you do get back just the 2 in the middle, you could use mod and floor div to do this. Here is an example – 789 % 10 = 9 and 789 // 10 = 78. See how using 10 with these operations makes one of them strip off the rightmost digit and the other give it back? You should be able to design a process to get whatever digit you want.

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# number is the number we are evaluating
# n is the nth digit from the right of the number
def find_digit(number, n):
    # Shift number to the right by n digits
    shifted_number = int(number / 10 ** (n-1))
    # Select the unit value as our digit
    shifted_digit = shifted_number % 10
    # Return our...

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