Assume a color display using 8 bits for each of the primary colors (red, green, and blue), per pixel and frame size of 1280 x 1024. What is the minimum size in bytes of the frame buffer to store a frame? How long would it take, at minimum, for the frame to be sent over a 100 Mbit/s network?
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The size expressed in bytes necessary to represent a single pixel is equal to the number of bits per primary color multiplied by the number of primary colors and the product is divided by the number of bits residing in a byte. So a single pixel requires 8 *3 /8=3 bytes....By purchasing this solution you'll be able to access the following files:
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