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5 kg of benzene are mixed with 5 kg of hexane.
Q 1(a) Determine the mole fractions for the mixture.
A 1(a) The molecular weight of benzene is 78.11 kg/kmole. The molecular weight of hexane is 86.18 kg/kmol. Thus we have: 5kg/(78.11 kg/kmole)=0.064 kmole=64 mole benzene and 5kg/(86.18 kg/kmole)=0.058 kmole =58 mole hexane. Their ratio in the mixture is: 64:58=52.5%:47.5% benzene:hexane....
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