For the Purpose of determining the distance between two points, a theodolite was set up at one point and a subtense bar 2m long between its targets was supported in its proper position at other point. If the measured angle between the targets on the bar was 3037’30’’, the horizontal distance between the two points was
A. 207.36 ft.
B. 103.68 ft.
C. 93.57 ft.
D. 51.84 ft.
To measure the angle DAE in fig. 36 of the text with a tape, each of the distances AB and AC was made 60 ft. If the distance from B to C was then found to be 89.50 ft, the angle DAE was
A tape that has an extra foot graduated to tenths outside the zero mark was used to measure a distance less than a tape length. When the rear tapeman held the 52 ft. graduation at his point, the head tapeman estimated the reading at his end of the measurement to be 68 hundredths of a foot. The length of the measurement should be recorded as
A. 52.68 ft.
B. 52.32 ft.
C. 51.68 ft.
D. 51.32 ft.
The length of a line was measured along sloping ground and was found to be 125.0 ft. and the angle of inclination between the horizontal and the ground was 15044’. To plot the line on a map, its length should be taken as
A. 125.00 ft.
B. 124.70 ft.
C. 120.60 ft.
D. 120.30 ft.
In order to erect a perpendicular to a line by the method indicated in Fig. 31. Of the text, the distance BC is made equal to 40ft. When the zero mark of a 100-ft tape is held at point B and a man at point D holds the 30 ft mark and the 34 ft mark together at that point, the line BD will be perpendicular to the line BC if the reading of the tape at point C is
A. 96 ft.
B. 94 ft.
C. 86 ft.
D. 84 ft.
In the Examination Figure the full lines represent the boundaries of a tract of land, the dimensions of which are as shown. It was found that the length of the diagonal BD could not be measured directly because of obstructions. Therefore the side BC was prolonged 80 ft to the point B’ and the side DC was prolonged to D’ just far enough to make the line B’D’ parallel to BD. The distance CD’ that should have been measured along the prolongation of DC was
A. 102.1 ft.
B. 99.2 ft.
C. 64.5 ft.
D. 62.7 ft.
If the length of line B’D’ in the Examination Figure is found to be 104.5 ft., the length of the diagonal BD is
A. 835.0 ft.
B. 654.4 ft.
C. 512.8 ft.
D. 383.5 ft.
In the examination Figure, the area of triangle BCD, to the nearest 10 sq. ft, is
A. 98,350 Sq ft.
B. 98, 180 Sq ft.
C. 11,490 Sq ft.
D. 11350 Sq ft.
The part of the tract in the Examination Figure between the auxiliary line AD and the irregular boundary DEIJA has been divided into right triangles and two trapezoids by perpendicular offsets measured at the given distances from D along the auxiliary line AD. The lengths of the perpendicular offsets E1E, I1I, and J1J are also shown. The total area of this part of the tract, to the nearest 10 Sqft., is
A. 18,740 Sq ft.
B. 12,280 Sq ft.
C. 12,190 Sq ft.
D. 9370 Sq ft.
The missing line key on a Total Station calculates the
A. Slope distance between two points.
B. Vertical angle between two points.
C. Horizontal & Vertical distance between two points.
D. Horizontal angle between two points.
This material may consist of step-by-step explanations on how to solve a problem or examples of proper writing, including the use of citations, references, bibliographies, and formatting. This material is made available for the sole purpose of studying and learning - misuse is strictly forbidden.
This is only a preview of the solution. Please use the purchase button to see the entire solution