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Remembering the formula for liquid compressibility. IfI have a tank of oil of volume 1 ft³ at 60 F and 3500 psia, with compressibility of 6 X 10-5(1/psi). and we assume oil compressibility is constant, and that the tank volume and temperature are constant, how much oil (volume) would have to be removed to drop the pressure to 2000 psia? Total volume As a % of the initial volume Plot V removed VS P from 2000 down to 500 psia. We have a mixture of 20% acetone, 40% benzene and 40% ethanol. Calculate: (If you use the spreadsheet make sure you have the right component names in the right cells and that the flash temperature is 35 C that doesn't automatically happen.. !!) 1) At 35 C, calculate the a) Bubble point pressure b) Bubble point vapor composition Dew point pressure d) Dew point liquid composition Bubble point temperature (at 1 atm) f) Dew point temperature (at 1 atm) 2) For a flash at 35 C and .19 atm a) the vapor fraction (V) For the flash the vapor composition For the flash, the liquid composition Field have observed the following field data 2600 psig Tres 180F Stock gravity separator gravity Stock tank gravity Separator GOR (R_..) 260 SCF/STB Stock Tank GOR(R. 60 SCF/STB Separator Pressure 114.7 Separator Temperature 100F Wellhead Pressure at feed separator) Production 200 STB/DAY Reservoir Pore Volume million BBL Water Saturation 20% (so oil occupies 80% pore volume) Wow that's lot! Calculate (using Excel of extra n°s (gas Combined gravity Bubble Point Pressure What viscosity? What What density? all liquid reservoir initially ? Gis P: Pb) s)What (initial oil formation volume factor) (RBL/STB original oil place (look units of Boi!) What Boi at the bubble point? What place the bubble point? How much oil produced to get down to the bubble point? pressure drops 300 psi below the bubble point, what Rsb? 14) What (use Rs from 10 and P = #3. 300) How much oil i the reservoir if no gas Now surface stuff conditions 114.7, Rs (V stock tank density? separator feed? We have acquired a gas field which was initially at 3500 psia. The pressure now is 2000 psia and 60 MMSCF of gas has been produced. Determine: (assume ideal gas law applies) a) Plot (excel) P vs Gp all the way to P = 0 b) Determine original gas in place (IGIP) c) At what pressure will 60% of remaining gas have been produced d) What are the remaining reserves (gas left in field) if abandonment pressure is 200 psia (that's when we stop producing whats left after 200 psia is "lost") e) Plot P/Z vs Gp using the Z function on Excel (PVTRDOv5) f) Using the plot from "e" what is IGIP

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