% Pc - condensor pressure
% Pr - intermediate pressure
% Pb - boilar pressure

% 1 - boilar outlet/turbine inlet
% 2 - feedwater heater inlet
% 3 - condensor inlet
% 4 - condensor outlet/pump 1 inlet
% 5 - pump 1 outlet
% 6 - feedwater heater outlet/ pump 2 inlet
% 7 - pump 2 outlet/boilar inlet
%%
clc;
close all;
clear all;

%% DATA
P1 = 90;
P2 = 8.251;
P5 = P2;
P6 = P2;
P7 = P1;
T1 = 500;
T3 = 40;
T4 = T3;
%% CALCULATIONS

% at state 4 - saturated liquid at 40 C
h4 = XSteam('hL_T',T4);
v4 = XSteam('vL_T',T4);
s4 = XSteam('sL_T',T4);

P4 = XSteam('psat_T',T4);
P3 = P4;
% at state 5
s5 = s4;
h5 = XSteam('h_ps', P5, s5);

% at state 6 - saturated liquid at 8.251 bar
h6 = XSteam('hL_p',P6);
v6 = XSteam('vL_p',P6);
s6 = XSteam('sL_p',P6);

% at state 7
s7 = s6;
h7 = XSteam('h_ps', P7, s7);

% at state 1 - superheated steam
h1 = XSteam('h_pt',P1,T1);
s1 = XSteam('s_pt',P1,T1);

% at state 2 - intermediate pressure
s2 = s1;
h2 = XSteam('h_ps',P2,s2);

% at state 3 - condensor pressure
s3 = s1

Exercise 1. Theme: Windowing NOTE: in a), you should choose a = 0....