QuestionQuestion

The following information is available from a wet gas reservoir:

Mid-point Depth= 5025 ft.
Pressure Gradient = 0.5 psi/ft.
Surface Temperature = 50oF
Temperature Gradient =1oF/100 ft.
Separator gas gravity = 0.63
Stock-tank gas gravity = 1.00
Separator gas rate = 4325 MCF/D
Stock-tank gas rate = 650 MCF/D
Stock-tank oil rate = 35 STB/D
Stock-tank Oil gravity = 47o API
A = 1780 acres
h = 13 ft.
φ = 8.5%
Swi =26%
The reservoir is completely surrounded by an aquifer with the following properties:
k = 100 md
h = 15 ft.
φ = 10%
μw = 1 cp
ct =7×10-6 1/psi

Calculate the reservoir pressure after producing at a constant separator gas rate of 4325 MCF/D for one year. You can ignore the water production.

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