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1. The core data, well logs, well tests, and PVT data for the oil reservoir were provided in the earlier homeworks. Wells 1, 2, 3, 4, and 10 were produced at a rate of 300 STB/D each for 645 days before they were shut-in for a buildup test. Determine the initial oil-in-place assuming this is a solution gas drive reservoir and Rp = 528 SCF/STB. You may ignore the rock and water expansion and the water production. 2. The following data are available from a saturated oil reservoir without a gas-cap: t p B. R2 Bg Rp years psia RB/STB SCF/STB RB/MCF SCF/STB 2500 1.498 721 1.048 1 2400 1.463 669 1.155 750 2 2300 1.429 617 1.280 1100 The reservoir contains 3 wells. Each well has been produced at a constant rate of 300 STB/D. The reservoir is surrounded by an aquifer with the following properties: Q 15% k 50 md 1cp a = 360° (full circle) Reservoir Area = 500 acres Determine the Initial Oil-in-Place (N) and the Aquifer Constant (B). You may ignore the rock and water expansion and the water production. 3. The following information is available from a volumetric wet gas reservoir: Mid-point Depth= 5025 ft. Pressure Gradient = 0.5 psi/ft. Surface Temperature = 50°F Temperature Gradient =1°F/100 ft. Separator gas gravity = 0.63 Stock-tank gas gravity = 1.00 Separator gas rate = 4325 MCF/D Stock-tank gas rate = 650 MCF/D Stock-tank oil rate = 35 STB/D Stock-tank Oil gravity = 47° API A = 1780 acres h 13 ft. $ = 8.5% Sni =26% A. Calculate the initial gas in place B. Calculate the reservoir pressure after one year assuming constant separator gas rate of 4325 MCF/D.Number range CHAPTER

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