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Problem 1: (10 points) Follo,ving information is available forma limestone gas reservoir. What is the secondary porosity? cl>NIG" 16 o/• Pb= 2.11 gr/cm' Át"" 81 μsec/ft Fluid is fresb water Problem 2: (10 points) In a gas reservoir, which is 50-50 limestone and dolomite, the bulk density is measured to be 2.62 gr/ce and the flushed zone resistivity is measured to be 15 ohm.m. I f the gas density is 0.2 gr/ce and the mud filtrate resistivity is 0.87 ohm.m at the formation temperature, \Vhat is the porosity of the formation? Fluid is fresh \Vater. Problem 3: (14 points) Completet he follo,ving table using the N-D and Pma-Ua maac rosslplots.S ho,v your work on the crossplot. No. Pe Pb(g/cc) cl>NLS Crossplot el> N-D Litbology Percentage (more likely) 1 2.44 0.21 LS:- 0/4 SS:-% DOL:-% 2 2.2 0.28 LS:-º/ • SS:-º/• DOL:-% Pmu-Um1L1i tbology Percentage 3 3.0 2.41 0.17 LS:-º/• SS:-% DOL:-% 4 3.2 2.50 0.20 LS:-•1. SS:-% DOL:-% Pr= 1.19 gr/ce ~d .ñlltd 8Qf1ho(lie:\ . tDXIt 'cd 1ndC .• Op ~J u , .. ,s '' ' .. r ' .~.. 2.0 ' ' .. S.,llu< ~os.• ' --~ ·11. • :,_ u -◄,¡, '!> __..,J S . '(¼.."' ~q.,.g*s •~ ;¡,"' -i> ...,. u •c-P4· .o . lO ' (1 .. , L "Y. ·~ ~ ~~~ W.tl-~~ 'P. ~ 2S 2.3 ' -~ ~.. .,,.., . ' ,f". ¡, lO . ,. . .,. ' ¡¡, u " o.,,,;,y , .. IS ..,... .. "" " ~·, , +,(μ) dtmity. p,(!l'cm'I ts ,<> "'- . 2.71g /Cfll'. ' 10 "'. tog./,,, .; .. ' 5 ~ ! ,. ~. , ' ,, t7 o u -S u .,. -IS lO Alil>IWH ' ' o 10 lO lO .. Corrtt1t'dl f)p.wel'll lírlenont fttutronpo,osit, y+o.u,t p.u.l __.,_ _,,, ·- u --•......,; - u r_;: n o • -IS 40 u 2.3 Appaf.tffl ITlltnJt greindensity, p_t gltm'I ·- ,., 2.5 ,.. ,., 18 10 11 ' .... ~ • < $ .•¡ • ;J K.feld$pa.r ' ,. ., .~ ,t .. ' ~ ~ ' ' s,, ' -~~ IÍClfe ., C-.ite .;.¡.1> " .... ~ e ~ • ;;,• ... " " ,. 16 Problem 4: (20 points) For the follováng log in the next page: a) ldentify the fluid in the zones "A" through "D". (4 points) Zone A: 5500-5538 ft Zone B: 5540-5590 ft Zone C: 5600-5630 ft Zone D: 5660-5720 ft b) For zone "A" which is a shaly sandstone zone, calculate the water saturation using Simandeaux method. The lithology in the clean zone is sandstone and humble equation is applicable. (16 polnts) Hint: Deep resistivity reads R. and for each zone read the AVERAGE R. value. p,oblem S: (10 polnt,) For 1he following log-log plol which includcs depths below OWC, PIOI Sw-500/4 and Sw=30% finesA. sSwnea • l.10 and n-2.10 and showyourcaloulations. _._.___ ·-. • - •••• - • ,-.-.. • •- ~• is • :,: 0.1 "- ' ' - - -- •- • -~- • 1 1 1 - ~ 1 1 ¡ - 1 1 1 1 11 1 1 lj 0.01 1 0.01 0.1 1 10 100 1000 Rt, ohm,m p-roblem 6: (1, polnts) Thef ollowingin íormationi s acquirtd froma dolomite oil rese,voir. Also~ lab analysisr esulu oa se--1 samplcs are reponed in below plocs. What is lhc moveable llydrocarbon satur¿tion? gr P• = 2.Stt gr Paf= lec 11., = 60ollmm R, = 25 olmtm RMf = 0.8 ohmm @Tr 11. ~ o.o, ohmm@T 1 lCIOO .i. .... o a: y=l.lllc u - R1 =0 .9965 111 ------ ---- , --'-- G.Ot 0.1 Porosltv, frac:tlon 1 10 -- --- - o § a: ---- y=0.98><'-"".;::,-_- - - ---1 R" • 1.00 ---- L...---- ----- O.\ "- - -- - - - ------- 0.1 1 Sw I.U:1,Ñ, ....... ..i T ,iwet Time A , (a,Sl'fo Vcloeitv (IWOC) Dolamole l.im..o.,.~. ..., .,. Anhydnte º""""' .,. W•ter (ltffh) W&tff (100 ,000 i,pm NaCI) W•t•r (.!'00.000 C>CMN'na Q) "••" c..ing 1 1 to U(t5Y OHIS~• - NH.11.SV ' ' 111 1 M• ' ' 1 1 1 1 1 ' 1.5 1 1 1 1 1 " 1 1 1 I! ! 1 ~ : : 1111 1 1 1 1 1 1 1 1 ~ ~ Naa .tldC I IIJ:>) ~ ' I1 1K, ' 1 1 11 1 ¡ t if L·i SOq ' ~5 ': N0,1o~r 1 1 ' 81t o,«I' ~ HCO, 1 '' 1- l11USr 1 1 1 . o . ' I' ~ ' 1 \ ftll :H 1 "°'' ' 1 11 ¡ ! 1 1 10 ,. "' ,., lQ) (j)I) 43.5 23,000 47 .5 2 1,000 SS.6 18,000 so.o 20,000 52.S 19 .000 67.0 15-.000 200 S,000 ""' S.300 l?G S.700 .=., <,000 1,088 $7 17 .000 to 1 1 1 1 1 1 ' . l ,, " 1 ' ' u 111! 1 ' '. ' 1 111 1 ! ~ '111 f ta t- .h::Rr~ s!--,..,c"""'L'1~:'- I- I so.~_ 1 ,- _\ ,-_ --1.J 1 ' ..' 11 HC0,11, _r- ' ' - o ,- ,.. 1i--irl-++i- Ht l--+-I -1t-H-ttt17.c l t"" Mg 1 _ l,ttl) 2,0:0 5.D'l) 10,0:0 20,COJ 50J.Q) 100,00:, 30QP» Totasl oli6,t OflCentratilopn(l l!ol,' I• 1•1 problcm 7: (8 polats) - ,. ronnalionw ater sam¡,lca nalysiss hows3 ,000 ppm Ca'' , 4,000 pprnS O, and 23,000 ppm NaCl. Wba1 Is1 hew ater n:sistivily,i í lhe fonna1ionI A:mperatunis, l 50ºFI COIWtnioano oroómtGilb y P.,: Ril fT1 . i-17Vllt•, ,nirFO f' R1~ R1I C,T• US.,1'1'J♦ 11S frt 10 r"'!::=:;=::=:,=s;=::========="" 8 o.ti - ~. ~ :'- ;.7 -...- ... . .. ,j¡CJ e o,c tnll'1don (11r1!n/sg_¡f atJS'fJ 11 ,, 21) 21 lD .. lO ,., tlO ",,". 3J) .., IO> '-"" ., .-.- - .. 'º·ª "" .'," .,. .. 111 ll m to KIO ,,. r:"".~i!!!..:.:..:.].-.'1 00> "t IO 211 lD " 121 140 HO 1IO :ZOO L._ __ ...... _ ...... _ ...... _ ...,-,..,,,..,..,,.....t.JJ.....J..J.....L.W.....WLU.....L / p,-oblem 8: (12 polnls) c31cuJattth e water resisti\fityin the intervaoJf 10,000-10,050 ft fromt hec onvcntionaml ethod. Tcmpera ture s,adient is 1.1 ºF/IOOft and annual suñace temperature is 60 º F. Rmirs measured2 .2 ohm.m@ 80 ºF. No thleknescso tTCtcion is required. 1 . .170 SP(MV) GR(APII 1 •• U"Lloli~ 10 1 10.1 ll.O(oh"'ml 10 1 ...... l 1,r: r- i" H+t-++H1 7°H-rt-t i1 '; ., ~ / ~ t-++t-ti4:~H~---t-ti-tit-1 ..~ r- Hti-t-Hi:fll""HTit 1?t1 "~ 1cr > 1<1"'" "' 1 ' r l l/ .... r- -r í r 10000 10010 10020 1 ' ~ 1 y~ t-t-f':lc-tttt+i ~ ti +H-1 100<0 11 10030 lt 1 l 1 1 f--i 11 1 !\ ~ 1 1 1 1 1 1 ' 1 l 11 1 1 11v 1 l] 1 Y. ' 1 1 1 )'i -tí 1 1--~ 1 '~ 1 ; i--R' - 1 1 l] I IIJ 11 l.~ 11 ~1111 10000 1 1 1 i 11 1

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