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1. (a) Write a MATLAB function x = bcksbst(U,b) that inputs a nonsingular upper triangular matrix U, and a column vector b of the same dimension and output will be a column vector x, which is the numerical solution of the linear system Ux = b obtained from the back substitution algorithm. (b) Use this function to solve the system Ux = b with 1 2 3 4 4 0 2 3 4 3 U = b = 0 0 3 4 2 0 0 0 4 1 (c) How much cpu time it takes in part (b) ? (d) Use U\b, MATLAB build-in function to solve (b), how much cpu time it takes? 2. By hand, not MATLAB, solve the following system without partial pivoting (no row interchange) - - + 6z2 + 9x3 = 39 3. Use MATLAB to generate a plot of size n of the Hilbert matrix H vs the quantity k = for n = 5.10.15 100. You will use MATLAB function hilb(n) to generate the Hilbert matrix of size n. What do you observe? Use appropriate scale for plot. (Note: k = is called the condition number of the matrix A and MATLAB has a built-in function cond(A, inf) to calculate this).

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function x=bcksbst(U,b)
%Input: U Uppertriangular square matric
%       b vector
%Output: x, solutions of Ux=b




for i=n-1:-1:1
    for j=n:-1:i+1

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