Question

Write an expression as a complex number in standard form:
1. (1 + i) + (3 + i)
2. (-4 - i) - (4 + 5i)
3. 3i(4 + 2i)
4. (2 + i)(4 + 2i)
5. -(3 + i)(7 - 3i)
6. (2 - i)²

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You should know that i² = -1
1. (1+i)+(3+i)=1+3+i+i=4+2i
2. (-4-i)-(4+5i)=-4-i-4-5i=-4-4-i-5i=-8-6i
3. 3i(4+2i)=12i+6i²=12i-6=-6+12...

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