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2)A) H₀:μ₁=μ₂=μ₃=μ₄;
Ha:μ₁≠μ₂≠μ₃≠μ₄
B) The summation of the expected counts for this test are approximately equal to the summation of the counts for each row. So for *: 20.84+21.58+*=64, where *=21.58.
The summation of the contributions to Chi-square can be calculated to find the missing value. So for **: .06424+.59346+.27173+.41687+.03054+**+.00545+.08343+.04677+.61768+.14915+.14915=2.64, where **=.21153...
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