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Q.1
function x=newton(f,df,x0,N,epsilon)

g=@(x) x-f(x)/df(x);
x(1)=x0;

%%% 1ère itération
x1=g(x0);
x(2)=x1;
e_n=abs(x1-x0);
errel=e_n/abs(x1);
nbiterations=1;
%%% itérations successives avec critères
while (errel>epsilon) &&(nbiterations <N)
          x0=x1;
          x1...

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