 # 1. Apair of dice is rolled. Sam says there are 36 outcomes in the s...

## Question

1. Apair of dice is rolled. Sam says there are 36 outcomes in the sample space for this procedure and Sally says there are 11 outcomes in the sample space. Explain how they could both be correct.

2. Suppose three fair coins are tossed and the number of heads that appear is recorded. What is the probability of getting exactly two heads?

3. We must create a license plate code that consists of two letters followed by three digits. The letters cannot repeat, but the digits may. How many such license plate codes can be formed?

4.A pizza can be made with any of the following toppings: Cheese, pepperoni, sausage, mushrooms, anchovies, green peppers, or olives. Doubling of any topping is not allowed. What is the probability that a randomly created three-topping pizza will contain mushrooms?

5. Suppose a game has four outcomes, A, B, C, and D. The probability of outcome A is 0.4, the probabilities of each of the other outcomes is 0.2. A player receives \$2 if outcome A occurs, \$3 if outcome B occurs, \$1 if outcome C occurs, and must pay \$5 if outcome D occurs. What is the mean value of one trial of this game?

6. Suppose a trial consists of rolling two dice and reporting the smaller of the two numbers rolled? What are the possible outcomes? Are they equally likely?

7. According to the Central Limit Theorem, how does the variance of averages over four observations compare to the variance of individual observations?

## Solution Preview

These solutions may offer step-by-step problem-solving explanations or good writing examples that include modern styles of formatting and construction of bibliographies out of text citations and references. Students may use these solutions for personal skill-building and practice. Unethical use is strictly forbidden.

Question 1
Answer:Sam is correct because he applies the Product Rule of Counting and each of the 6 possible outcomes of one dice (1,2,3,4,5,6) can be paired-up with any of the 6 possible outcomes of the 2nd dice (1,2,3,4,5,6) for a total of 6 * 6 = 36 outcomes.

Sally is also correct because she thinks to the possible sums of the values of the two dice. The sum can have any of the following 11 values:2 (1+1), 3 (1+2 or 2+1), 4 (1+3, 2+2, 3+1), 5 (1+4, 2+3 or mirrored results), 6 (1+5, 2+4, 3+3 and mirrored outcomes), 7 (1+6, 2+5, 3+4 and mirrored outcomes), 8(2+6, 3+5, 4+4 and mirrored outcomes), 9 (3+6, 4+5 and mirrored results), 10 (4+6, 5+5, 6+4), 11 (5+6, 6+5), and 12(6+6)....

By purchasing this solution you'll be able to access the following files:
Solution.pdf.

\$20.70
for this solution

or FREE if you
register a new account!

PayPal, G Pay, ApplePay, Amazon Pay, and all major credit cards accepted.

### Find A Tutor

View available Probability Tutors

Get College Homework Help.

Are you sure you don't want to upload any files?

Fast tutor response requires as much info as possible.