1. 0.66/1 points | Consider a finite population with five elements...

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1. 0.66/1 points | Consider a finite population with five elements labeled A, B, C, D, and E. Ten possible simple random samples of size 2 can be selected. (a) List the 10 samples beginning with AB, AC, and so on. (Enter your answers as a comma-separated list.) AB,AC,AD,AE,BC,BD,BE,CD,CE,DE (b) Using simple random sampling, what is the probability that each sample of size 2 is selected? (Enter your probability as a fraction.) 1 (c) Assume random number 1 corresponds to A, random number 2 corresponds to B, and so on. List the simple random sample of size 2 that will be selected by using the random digits 8, 0, 5, 6, 5, 4, 1. 2. 0/1 points I A student government organization is interested in estimating the proportion of students who favor a mandatory "pass-fail" grading policy for elective courses. A list of names and addresses of the 645 students enrolled during the current quarter is available from the registrar's office. Using three-digit random numbers in row 10 of the table of random numbers and moving across the row from left to right, identify the first 10 students who would be selected using simple random sampling. The three-digit random numbers begin with 816, 283, and 610. (Enter your answers as a comma-separated list.) 1816,283,610,039,254,568,353,763,602,421. -/1 pointsASWESBE9 7.E.011. The following data are from a simple random sample. 5 8 11 7 10 13 (a) What is the point estimate of the population mean? (b) What is the point estimate of the population standard deviation? (Round your answer to one decimal place.) 2. -/1 pointsASWESBE9 7.E.015.MI. According to a certain website, wine critics generally use a wine-scoring scale to communicate their opinions on the relative quality of wines. Wine scores range from 0 to 100, with a score of 95-100 indicating a great wine, 90-94 indicating an outstanding wine, 85-89 indicating a very good wine, 80-84 indicating a good wine, 75-79 indicating a mediocre wine, and below 75 indicating that the wine is not recommended. Random ratings of a pinot noir recently produced by a newly established vineyard in 2018 follow: 89 91 88 82 74 91 62 77 82 79 85 96 (a) Develop a point estimate of mean wine score for this pinot noir. (b) Develop a point estimate of the standard deviation for wine scores received by this pinot noir. . (Round your answer to four decimal places.)1. -/1 pointsASWESBE9 7.E.019. You may need to use the appropriate appendix table or technology to answer this question. A population has a mean of 800 and a standard deviation of 200. Suppose a sample of size 400 is selected and x is used to estimate u. (Round your answers to four decimal places.) (a) What is the probability that the sample mean will be within +5 of the population mean? (b) What is the probability that the sample mean will be within 10 of the population mean? 2. -/1 pointsASWESBE9 7.E.023. You may need to use the appropriate appendix table or technology to answer this question. Suppose we are interested in the Annual Salary of Electronics Associated, Inc. (EAI) managers and we find that for a sample of n = 30 managers, there was 0.5034 probability of obtaining a sample mean within $500 of the population mean (see the figure below). Sampling distribution of X OF = 730.30 P(51,300 s X < 52,300) P(T < 51,300) x 51,300 51,800 52,300 i For parts (a) and (b), let the sample mean be 51,800 and O = 4,000. (Round your answers to four decimal places.) (a) What is the probability that X is within +$500 of the population mean if a sample of size 60 is used? (b) Answer part (a) for a sample of size 120.3. -/1 pointsASWESBE9 7.E.024. You may need to use the appropriate appendix table or technology to answer this question. Barron's reported that the average number of weeks an individualis unemployed is 16.5weeks. Assumethat for the population of all unemployed individuals the population mean length of unemployment is 16.5 weeks and that the population standard deviation is 6 weeks. Suppose you would like to select a sample of 60 unemployed individuals for a follow-up study. (a) Show the sampling distribution of X, the sample mean average for a sample of 60 unemployed individuals. weeks -2.4 - -1.6 -0.8 0.8 1.6 2.4 weeks -1.5 4.5 10.5 16.5 22.5 28.5 34.5 i i weeks weeks 14.1 14.9 15.7 16.5 17.3 18.1 18.9 57.6 58.4 59.2 60 60.8 61.6 62.4 i C i (b) What is the probability that a simple random sample of 60 unemployed individuals will provide a sample mean within 1 week of the population mean? (Round your answer to four decimal places.) (c) What is the probability that a simple random sample of 60 unemployed individuals will provide a sample mean within 1 week of the population mean? (Round your answer to four decimal places.) 2/34. -/1 pointsASWESBE9 7.E.027.MI. You may need to use the appropriate appendix table or technology to answer this question. The Economic Policy Institute periodically issues reports on workers' wages. Suppose the institute reported that mean wages for male college graduates were $37.39 per hour and for female college graduates were $27.83 per hour in 2017. Assume the standard deviation for male graduates is $4.60 and for female graduates it is $4.10. (Round your answers to four decimal places.) (a) What is the probability that a sample of 60 male graduates will provide a sample mean within $1.00 of the population mean, $37.39? (b) What is the probability that a sample of 60 female graduates will provide a sample mean within $1.00 of the population mean, $27.83? (c) In which of the preceding two cases, part (a) or part (b), do we have a higher probability of obtaining a sample estimate within $1.00 of the population mean? Why? part (a), because the standard error is lower part (b), because the standard error is higher part (b), because the standard error is lower part (a), because the standard error is higher (d) What is the probability that a sample of 110 female graduates will provide a sample mean more than $0.60 below the population mean, $27.83? 5. -/1 pointsASWESBE9 7.E.029.MI. You may need to use the appropriate appendix table or technology to answer this question. Suppose the CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100. (a) What is the probability that the mean price for a sample of 20 federal income tax returns is within $16 of the population mean? (Round your answer to four decimal places.) (b) What is the probability that the mean price for a sample of 60 federal income tax returns is within $16 of the population mean? (Round your answer to four decimal places.) (c) What is the probability that the mean price for a sample of 81 federal income tax returns is within $16 of the population mean? (Round your answer to four decimal places.) (d) Which, if any, of the sample sizes in parts (a), (b), and (c) would you recommend to ensure at least a 0.95 probability that the sample mean is within $16 of the population mean? (Select all that apply.) 20 customers 60 customers 81 customers none of the above 3/31. - -/1 pointsASWESBE9 7.E.031. A sample of size 90 is selected from a population with p = 0.50. (a) What is the expected value of p? (b) What is the standard error of p? (Round your answer to four decimal places.) (c) Show the sampling distribution of p. p p - -0.15 - -0.10 - -0.05 0.00 0.05 0.10 0.15 0.35 0.40 0.45 0.50 0.55 0.60 0.65 i i p - -2 -1 1 2 3 p - -0.10 - -0.05 0.00 0.05 0.10 0.15 0.20 i i (d) What does the sampling distribution of p show? The probability distribution of p is approximately normal with a mean of 0.05. The probability distribution of p is approximately normal with a mean of 0. The probability distribution of p is approximately normal with a mean of 0.50. The probability distribution of p is approximately normal with a mean of 90.Chapter 7.6 Homework 2. -/1 pointsASWESBE9 7.E.033.MI. Assume that the population proportion is 0.55. Compute the standard error of the proportion, op for sample sizes of 100, 200, 500, and 1,000. (Round your answers to four decimal places.) For a sample size of 100 For a sample size of 200 For a sample size of 500 For a sample size of 1000 What can you say about the size of the standard error of the proportion as the sample size is increased? of approaches p as n increases. p or approaches p as n increases. p of decreases as n increases. p of increases as n increases. 3. -/1 pointsASWESBE9 7.E.035. You may need to use the appropriate appendix table or technology to answer this question. The president of Doerman Distributors, Inc., believes that 35% of the firm's orders come from first-time customers. A random sample of 200 orders will be used to estimate the proportion of first-time customers. (a) Assume that the president is correct and p = 0.35. What is the sampling distribution of p for n = 200? (Round your answer for of to four p decimal places.) T- = Sp E(p) = Since np = and n(1 - p) = , approximating the sampling distribution with a normal distribution Select- C appropriate in this case. (b) What is the probability that the sample proportion p will be between 0.25 and 0.45? (Round your answer to four decimal places.) (c) What is the probability that the sample proportion will be between 0.30 and 0.40? (Round your answer to four decimal places.) 2/34. -/1 pointsASWESBE9 7.E.041.MI. You may need to use the appropriate appendix table or technology to answer this question. The Food Marketing Institute shows that 17% of households spend more than $100 per week on groceries. Assume the population proportion is p = 0.17 and a sample of 800 households will be selected from the population. (a) Show the sampling distribution of p, the sample proportion of households spending more than $100 per week on groceries. p p -1.83 -0.83 0.17 1.17 2.17 0.144 0.157 0.17 0.183 0.196 i i P P - -0.013 0 0.013 0.026 0.039 - -0.026 - 0.013 0.013 0.026 i i (b) What is the probability that the sample proportion will be within +0.02 of the population proportion? (Round your answer to four decimal places.) (c) Answer part (b) for a sample of 1,600 households. (Round your answer to four decimal places.) 3/3

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