# Physics Questions

## Transcribed Text

1. The tide in 4 kilometer deep water has twice the celerity of the tide in 1 km of water. From the equations for wave celerity, show if this is true or false. 2. How deep is the Bay of Fundy, if it is 200 kilometers long and acts as a quarter wavelength resonator, resonant with a 12 hour 25 minute tide? The relevant equations are celerity C= 2/T = (g H)1/2 ==1/4, so T=4L (g H>-1/22 solve for H. L sea s.riace H Depth of Bay of Fundy Bay of Fundy length 3. A tsunami has a wavelength ~ 100 kilometers. What is the celerity in 4 kilometers of water? What is the celerity in 10 meters of water? 4. What is the volume transport of the Gulf Stream in Sverdrup units if the Gulf Stream is 100 km wide and 1.5 kilometers deep, at a velocity of 1.5 meters per second? 5. In a developed sea of deep water waves with. Wind speed: 20 km/hr 40 km/hr 80 km/hr Average height: 0.33 m 1.8 m 10.3 m Wavelength 10.6m 22.2m 158.6m Compute the celerity of each average wave. 6. Compute which waves are breaking waves in # 5. 7. You are fishing in 4 meters of water. There is an ocean swell passing regularly. The period is about 10 seconds. a) What is the celerity of the swell in the open-ocean? b) What is the celerity of the wave passing under your boat? 8. What is the volume transport in Sverdrup units of the equatorial undercurrent? Assume it to be a jet lying between 50 and 250 meters depth, width of 100 km and length of 12000 km, with celerity of 2.5 m/sec? How does this compare with the Gulf stream above? 9. What is the value of the Coriolis parameter at the pole, using the equations given in slides 21 and 27, lecture on advective processes? 10. The ocean has a volume of 1x109 km³, as you computed in the previous problem set. If ice loss for Greenland and Antarctica is 500 km³ per annum, how much does the ocean level rise from that source?

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4) One Sverdrup is equal to one million cubic meters per second.

(100000) (1500) (1.5) = 225000000 cubic meters per second.
This is equivalent to 225 Sverdrups.

5) The celerities are:
(9.8 * 10.6 / (2pi))^(1/2) = 4.07
(9.8 * 22.2 / (2pi))^(1/2) = 5.88
(9.8 * 158.6 / (2pi))^(1/2) = 15.73

6)
0.33 / 10.6 = 0.031
not breaking

1.8 / 22.2 = 0.081
breaking

10.3 / 158.6 = 0.0649
not breaking...
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