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Solution (a) Find the magnitude of the centripetal acceleration when U = 50.0m/s. Substitute into Equation 7.13: a. C = - "² r 6.25 (50.0 m / s) 2 = m/ S 2 4.00 X 10² m (b) Find the angular speed. Solve Equation 7.10 for w and substitute: 50.0 m/s = r = 0.125 rad/s 4.00 X 10² m (c) Find the magnitude of the tangential acceleration. Divide the change in linear speed by the time: - a = 01 40.0 m/s = 4.00 m/s² Ui 60.0 m/s - st 5.00 S (d) Find the magnitude of the total acceleration. Substitute into Equation 7.18: a = Vai - a'= V (4.00 m/s²)² + (6.25 m/s²)² a = 7.42 m/s²

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General Physics Questions
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