 # Physics Questions

Subject Physics Physics - Other

## Question

*A patient has a temperature of 100.5 oF. Convert this temperature to centigrade.

* A patient has a temperature of 37.25 oC. Convert this temperature to Fahrenheit.

* Convert 225 Kcal to joules.

* Energy is being produced at the rate of 12,500 watts. What is this rate in Kcal/h?

* How much oxygen, in liters, is required to produce 125 Kcal of energy?

* How much is need to produce 12,500 J of energy? In liters

* How much energy is required to walk 5 miles in 1.5 hours? (Round answer to two significant figures.)

* If a 5 mile walk (as in problem 7) is completed in 1 hour and 30 minutes, what is the power output of the walker? (Round answer to two significant figures.)

* What is a person's energy requirement in a day when he:
sleeps 8 hours (72Kcal/h),
sits at a desk for 3 hours (102.5Kcal/h),
does moderate activity for 7 hours (228Kcal/h),
does light activity for 2 hours (180Kcal/h) and
relaxes for 4 hours (108Kcal/h)? (Round answer to two significant figures)

A. How much heat is produced when 275 Kcal work is done at only 7.5% efficiency? (Round answer to two significant figures.)
B. What is the change in the body's internal energy? (Round answer to two significant figures.)
C. How much oxygen is used? (Round answer to two significant figures.)

* A person has an exposed body area of 1.2 m2 and a body temperature of 37 oC. What is his heat loss by radiation if the surrounding walls are at a temperature of 22.5 oC? (Round answer to two significant figures)

* A person's total energy consumption is 600 kcal while performing an activity with an efficiency of 5%. How much excess heat was generated? (Round answer to two significant figures.)
In Kcal

## Solution Preview

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1. A patient has a temperature of 100.5 oF. Convert this temperature to centigrade.
the formula is C/5=(F-32)/9
So C=(5/9)*(F-32 )=(5/9)*(100.5-32)= 38.05556 deg C

2. A patient has a temperature of 37.25 oC. Convert this temperature to Fahrenheit.
The formula is C=(5/9)*(F-32 ) so (9/5)*C+32 =F
So (9/5)*(37.25)+32 =F
Or F =99.05 deg F

3. Convert 225 Kcal to joules.
Now 1cal = 4.184 Joule
Using dimension analysis
1kcal =1000 cal =1000*4.184 J =4184 J...

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