Let T(n) be defined recursively as follows:
T(11)= -11 and T(n)= 2T(Floor(n/2)+5) +n for all n≥12. Prove by induction on n that T(n)≤(n-10)log(n-10) -11 for all integers n≥11.

Let T(n) be defined recursively as follows: T(n)=4T(n/2) + n² (note that for sufficiently small n, T(n) is bounded by a constant). Use the Master Theorem to solve this recurrence relation up to a constant factor.

Same as part c) except this time T(n)=3T(n/2)+n.

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T(11) = - 11
T(n)=2*T(FLOOR(n/2)+5)+n, (∀) n ≥12.
We must prove using induction that T(n)≤(n-10)*log⁡〖(n-10)〗-11 (∀) n ≥11.
P(n): T(n)≤(n-10)*log⁡〖(n-10)〗-11 (∀) n ≥11....

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