2) What is the "0 element" of P(S)?
The “1” element must satisfy the Identity and Compliment Laws for D6.
Namely, a*1=a for any element a from D6 and a "plus" its complement =1 for any element from D6.
We conclude that 6∈D6 is the “1” element because:
a*6 =a for any element of D6 (see below why)....
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